0=3x^2-400x

Solution for 0=3x^2-400x equation:

0=3x^2-400x

We move all terms to the left:

0-(3x^2-400x)=0

We add all the numbers together, and all the variables

-(3x^2-400x)=0

We get rid of parentheses

-3x^2+400x=0

a = -3; b = 400; c = 0;
Δ = b2-4ac
Δ = 4002-4·(-3)·0
Δ = 160000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{160000}=400$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(400)-400}{2*-3}=\frac{-800}{-6}
=133+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(400)+400}{2*-3}=\frac{0}{-6}
=0
$